Function Argument's Default Value Equal To Another Argument
Is it possible to define a function argument's default value to another argument in the same function definition? Something like: def func(a, b=a): print a, b but that didn't wo
Solution 1:
No. This is not possible. The Python interpreter thinks that you want to assign the default value of argument b
to a global variable a
when there isn't a global variable a
.
You might want to try something like this:
deffunc(a, b=None):
if b isNone:
b = a
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