Open File Knowing Only A Part Of Its Name

I'm currently reading a file and importing the data in it with the line: # Read data from file. data = np.loadtxt(join(mypath, 'file.data'), unpack=True) where the variable mypath

Solution 1:

You can use the glob module. It allows pattern matching on filenames and does exactly what you're asking

import glob

for fpath in glob.glob(mypath):
    print fpath

e.g I have a directory with files named google.xml, google.json and google.csv.

I can use glob like this:

>>> import glob
>>> glob.glob('g*gle*')
['google.json', 'google.xml', 'google.csv']

Note that glob uses the fnmatch module but it has a simpler interface and it matches paths instead of filenames only.

You can search relative paths and don't have to use os.path.join. In the example above if I change to the parent directory and try to match file names, it returns the relative paths:

>>>import os>>>import glob>>>os.chdir('..')>>>glob.glob('foo/google*')
['foo/google.json', 'foo/google.xml', 'foo/google.csv']

Solution 2:

I simple solution would be to use the python modules "os" and "re":

import os
import re
for file inos.listdir(mypath):
     if re.match("file_\d+\.data", file):
     ...

Solution 3:

Try

import os

[os.path.join(root, f) for root, _, files inos.walk(mypath)
                       for f in files
                       if f.startswith('file') and f.endswith('.data')]

It'll return a list of all files file*.data, in case there are more than one. You can just iterate through them. If there is only one file, then just put [0] at then end of the list comprehension.