Mimic Curl In Python

The following curl code works: curl --form addressFile=@t.csv --form benchmark=Public_AR_Census2010 http://geocoding.geo.census.gov/geocoder/locations/addressbatch t.csv is simply

Solution 1:

One option would be to use requests:

import requests

url = "http://geocoding.geo.census.gov/geocoder/locations/addressbatch"data = {'benchmark': 'Public_AR_Census2010'}
files = {'addressFile': open('t.csv')}

response = requests.post(url, data=data, files=files)
print response.content

prints:

"1"," 800 Wilshire Blvd,  Los Angeles,  CA,  90017","Match","Exact","800 Wilshire Blvd, LOS ANGELES, CA, 90017","-118.25818,34.049366","141617176","L"

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In case you need to handle the csv data in memory, initialize a StringIO buffer:

fromStringIO importStringIO
import requests

csv_data = "1, 800 Wilshire Blvd, Los Angeles, CA, 90017"
buffer = StringIO()
buffer.write(csv_data)
buffer.seek(0)

url = "http://geocoding.geo.census.gov/geocoder/locations/addressbatch"
data = {'benchmark': 'Public_AR_Census2010'}
files = {'addressFile': buffer}

response = requests.post(url, data=data, files=files)
print response.content

This prints the same result as is with using a real file.