Python Search For Input In Txt File

When my script is run, it asks for an input. That input is then checked to see if it's in a text file. If it is, text is printed. The code I have below is what I have but it doesn'

Solution 1:

The expression

line.strip().split('\n')

is not mutating the information bound to the name line, which remains unchanged. Instead it returns a new value. You need to bind that new value to a name in order to use use it. This example might help:

In [1]: a = "  v  "

In [2]: a.strip()
Out[2]: 'v'In [3]: a
Out[3]: '  v  'In [4]: b = a.strip()

In [5]: a
Out[5]: '  v  'In [6]: b
Out[6]: 'v'

Then split('\n') (note that you probably want \ instead of /) further returns a list of substrings split by newlines. Note that this is not very useful because for line in file: already splits over lines so the list would have one element at most, and so you should omit it.

Solution 2:

Here is the Answer :

discordname = input("What's your discord name?: ")
withopen('rtf.txt', 'r') as f:
    for line in f.readlines():
        if line.startswith(discordname):
            print ("it works")

I hope it resolve you're problem.thanks

Solution 3:

You are probably trying to get strings as input as well. I suggest this:

discordname = raw_input("What's your discord name? ")
withopen('rtf.txt') as f:
    for line in f:
        if discordname in line:
            print"works"

Solution 4:

You are trying to make the code more complex. Firstly to open a text file use 'with', because it is more flexible and doesn't need closing. Then, instead of using strip, you can use readlines(). This function converts each line into a list or you can also use method read(), which displays all results as it is.

So,

By using readlines, you can look through the user input in a line as a list, and by using read, you can look through each words. Here is the Solution:

discordname = input("What's your discord name? ")
withopen('rtf.txt') as file:
       contents = file.readlines()
if discordname in contents:
       print("It exits")

Solution 5:

Works for me, Optimized code is:

result=any(line.startswith(discordname) for line in file.splitlines())
if(result):
    file.close()
    print "works"