Loop Character A/b Alternately

How can I print A/B character alternately in python loop? What I expect in result: oneA twoB threeA fourB ...

Solution 1:

You can use itertools.cycle to repeat through a sequence. This is typically used with zip to iterate through a longer list, while repeating the shorter one. For example

import itertools
for i,j inzip(['one', 'two', 'three', 'four'], itertools.cycle('AB')):
    print(i+j)

Output

oneA
twoB
threeA
fourB

Solution 2:

try this:

l1 = ['A','B']
l2 = ['one','two','three','four']
for i,val inenumerate(l2):
    print(val + l1[i%len(l1)])

Solution 3:

You could also try using the modulus operator % on the index of an incremented for loop for the numbers to alternate the letters:

list_num = ['one', 'two', 'three', 'four', 'five', 'six']
list_alpha = ['A', 'B']
list_combined = []
for i in range(0, len(list_num)):
    list_combined.append(list_num[i] + (list_alpha[1] if i % 2else list_alpha[0]))
list_combined
>>> ['oneA', 'twoB', 'threeA', 'fourB', 'fiveA', 'sixB']

Solution 4:

Something like:

alternate_words = ['A', 'B']
    count = 0while count < 5:
    print count+1, alternate_words[count % len(alternate_words)]
    count += 1

Output:

1 A

2 B

3 A

4 B

5 A

Solution 5:

I think this will help ->

a1 = ['A','B']
a2 = ['one','two','three','four']
for i in range(len(a2)):
    print a2[i]+a1[i%2]