Using "apt-get Install Xxx" Inside Python Script
Solution 1:
You can use check_call
from the subprocess
library.
from subprocess import STDOUT, check_call
import os
check_call(['apt-get', 'install', '-y', 'filetoinstall'],
stdout=open(os.devnull,'wb'), stderr=STDOUT)
Dump the stdout
to /dev/null
, or os.devnull
in this case.
os.devnull
is platform independent, and will return /dev/null
on POSIX and nul
on Windows (which is not relevant since you're using apt-get
but, still good to know :) )
Solution 2:
Thank guys ! I use part of each solution. My code:
proc = subprocess.Popen('apt-get install -y FILE', shell=True, stdin=None, stdout=open(os.devnull,"wb"), stderr=STDOUT, executable="/bin/bash")
proc.wait()
Added: stdout and .wait
Thank you one more time from Argentina !
Solution 3:
For this particular task, as an alternative to subprocess
you might consider using Fabric, a python deployment tool to automate builds.
Solution 4:
This is meant as an addition to Russell Dias's accepted answer. This adds a try and except block to output actionable error information rather than just stating there was an error.
from subprocess import check_call, CalledProcessError
import os
try:
check_call(['apt-get', 'install', '-y', 'filetoinstall'], stdout=open(os.devnull,'wb'))
except CalledProcessError as e:
print(e.output)
Solution 5:
Use this to redirect the output to /dev/null:
proc = subprocess.Popen('apt-get install -y filetoinstall', shell=True, stdin=None, stdout=open("/dev/null", "w"), stderr=None, executable="/bin/bash")
proc.wait()
The call to .wait() will block until the apt-get is complete.
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