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Problem Sending An Httpget With Pycurl

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I am having problems converting the following curl command into PyCurl: curl -k --cert /tmp/blablabla 'https://blablabla' My attempt so far is shown below: c = pycurl.Curl() c.seto

Solution 1:

Add "--libcurl example.c" to your curl command line to get to see better what libcurl options curl uses, then you can copy them into your pycurl program rather swiftly.


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